How to use find with variable parameters? (Solved)

[arivas_2005]

greetings

i find and select file for extension.
i have the code

Code: Select all

declare -a finales
finales[1]=".docx"
finales[2]=".sxw"
finales[3]=".sxc"
finales[4]=".odt"

for NUM  in {1..4}; do
   find /Z_SECCION/1 -maxdepth 1 -type f -name ${finales[$NUM]} 
   #find /Z_SECCION/1 -maxdepth 1 -type f -name ${finales[NUM]} 
   ## echo ${finales[$NUM]}
   # echo ${finales[NUM]}
done

not work
How to use find with variables as parameters

thanks!

[arivas_2005]

Excuse me ... the problem was the asterisko

Code: Select all

finales[1]="*.docx"
finales[2]="*.sxw"
finales[3]="*.sxc"
finales[4]="*.odt"
for NUM  in {1..4}; do
   find /Z_SECCION/1 -maxdepth 1 -type f -name "${finales[$NUM]}"
done
 

Thank you again for your attention.

[april]

What does the directory structure look like that you are finding files in?
I'm seeing /Z_SECCION/1 is that correct?

I changed to "/TempSave/Scripts"
and got this error

Code: Select all

# bash findvarious.sh
find: paths must precede expression: colour2.sh
Usage: find [-H] [-L] [-P] [-Olevel] [-D help|tree|search|stat|rates|opt|exec] [path...] [expression]
find: `/TempSave/Scripts': No such file or directory
find: `/TempSave/Scripts': No such file or directory
find: `/TempSave/Scripts': No such file or directory

colour2.sh appears to be the first file found.
This was what my script looked like

Code: Select all

#!/usr/bin/findvarious.sh

declare -a finales
finales[1]="*.sh"
finales[2]="*.sxw"
finales[3]="*.sxc"
finales[4]="*.odt"
#finales[1]=".docx"
#finales[2]=".sxw"
#finales[3]=".sxc"
#finales[4]=".odt"

for NUM  in {1..4}; do
   find /TempSave/Scripts/ -maxdepth 1 -type f   -name ${finales[$NUM]} 
   #find /Z_SECCION/1 -maxdepth 1 -type f -name ${finales[NUM]}
   ## echo ${finales[$NUM]}
   # echo ${finales[NUM]}
done

#Excuse me ... the problem was the asterisko
#Code:	
#finales[1]="*.docx"
#finales[2]="*.sxw"
#finales[3]="*.sxc"
#finales[4]="*.odt"


#Thank you again for your attention.          arivas_2005

[MochiMoppel]

@arivas_2005: Please mark your thread as [solved] when you have found the solution to your problem.
It was not clear to me and probably not for april that you don't need any further help.

You seem to love arrays

If not using them is OK for you and if not even using find is OK you could simply use bash:

Code: Select all

shopt -s nullglob
printf "%s\n" "/Z_SECCION/1/"{*.docx,*.sxw,*.sxc,*.odt}

Unless you have dozens of extensions to search for you could use find without a loop:

Code: Select all

find "/Z_SECCION/1" -maxdepth 1 -name '*.docx' -o -name '*.sxw' -o -name '*.sxc' -o -name '*.odt' 

...and if your version of find supports it you could use regex and make the code a bit shorter:

Code: Select all

find "/Z_SECCION/1" -maxdepth 1 -regextype gnu-awk -regex ".*\.(docx|sxw|sxc|odt)$"

...and if it has to be a loop:

Code: Select all

for ext in docx sxw sxc odt; do
	find "/Z_SECCION/1" -maxdepth 1 -name *.$ext
done

Buena suerte

[april]

I am fully aware he has solved it but the subject interests me including your post which somewhat blows me away. Scripting capabilities are just mindblowing. Much food for thought.

[musher0]

Very interesting discussion.

[arivas_2005]

regards
here again
excuseme for opening this thread again
but I have the same problem
and I can not find you out

the scriptillo is

Code: Select all

#!/bin/bash
 comand0=$(Xdialog --title "Preparando los detalles de limpieza en Z_SECCION" \
		--stdout --separator "~" --inputbox "$MENSAJE""Intro command grep with params values Ej: grep -v -i "tre\|fou"" 12 110 "grep")
  cd /Z_SECCION/1
    OLDIFS=$IFS ; IFS=$'\n'
        # line command work fine  ---------------------------
		#for i in $(find ./ -type d ! -iname '*--*' | grep -i -v 'tre\|fou' | sed 's/..//'); do rm -rf $i ; done
		# but, grep in variable comand0 not work  -----------
		for i in $(find ./ -type d ! -iname '*--*' | $comand0 | sed 's/..//'); do rm -rf --no-preserve-root $i ; done
   IFS=$OLDIFS

I want to mix grep with find but passing grep in variable
ex: grep -v -i "tre\|fou"
Online command works perfect, but
when entering it in variable gives the error:
: line 8: grep -i -v 'tre\|fou': command not found grep -v -i "tre\|fou"
what will be the trick to make it work
again thanks for the support

[arivas_2005]

eureka!

after insistent 7 hours of trial and error.
I found the arrangement.
Thank you for the opportunity
Here I leave my scriptillo that works.

Code: Select all

#!/bin/bash
 cd /Z_SECCION/1
  CONDITION=`Xdialog --stdout --inputbox "parametro para find " 8 125 ""`
#   # funciona con CADENA y eval-------------------------------------------
 TMP=$IFS; IFS=$'\n'
  CADENA="find ./ -type d ! -iname '*--*' | "$CONDITION" | sed 's/..//'"
  for i in $(eval $CADENA); do rm -rf $i ; done
  IFS=$TMP  
# grep -i -v "tre\|cua"  for Xdialog

these lines are the solution
CADENA="find ./ -type d ! -iname '*--*' | "$CONDITION" | sed 's/..//'"
$(eval $CADENA)
I spent my Sunday
greetings for all!

[MochiMoppel]

regards
here again
excuseme for opening this thread again
but I have the same problem

This thread has nothing to do with your problem.

Indeed you already described the same problem, but in a different thread. The answer you received should give you a clue why you receive an error and how to avoid it.

Edit: I somehow didn't notice your last post. Anyway, it seems you could have saved some hours by learning from your own threads .

[arivas_2005]

my greeting @MochiMoppel
effectively. the key was in the thread:
http://www.murga-linux.com/puppy/viewtopic.php?t=110667
In a moment of lucidity, From there I re-took the idea.
but, while there is confusion, the path is not found.
thanks for your comments
and thank you for the support you offer in this medium
successes!
arivas